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Display information for equation id:math.2555.51 on revision:2555

* Page found: Das ideale Fermigas (eq math.2555.51)

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TeX (original user input):

\begin{align}

& I=\int_{-\infty }^{\infty }{{}}dx{{x}^{2}}\frac{{{e}^{x}}}{{{\left( {{e}^{x}}+1 \right)}^{2}}}=2\int_{0}^{\infty }{{}}dx{{x}^{2}}\frac{{{e}^{x}}}{{{\left( {{e}^{x}}+1 \right)}^{2}}}=-2\left[ {{x}^{2}}\frac{1}{\left( {{e}^{x}}+1 \right)} \right]_{0}^{\infty }+4\int_{0}^{\infty }{{}}dx\frac{x}{\left( {{e}^{x}}+1 \right)} \\

& \left[ {{x}^{2}}\frac{1}{\left( {{e}^{x}}+1 \right)} \right]_{0}^{\infty }=0 \\

& \int_{0}^{\infty }{{}}dx\frac{x}{\left( {{e}^{x}}+1 \right)}=\frac{{{\pi }^{2}}}{12} \\

& \Rightarrow I=\frac{{{\pi }^{2}}}{3} \\

\end{align}

TeX (checked):

{\begin{aligned}&I=\int _{-\infty }^{\infty }{}dx{{x}^{2}}{\frac {{e}^{x}}{{\left({{e}^{x}}+1\right)}^{2}}}=2\int _{0}^{\infty }{}dx{{x}^{2}}{\frac {{e}^{x}}{{\left({{e}^{x}}+1\right)}^{2}}}=-2\left[{{x}^{2}}{\frac {1}{\left({{e}^{x}}+1\right)}}\right]_{0}^{\infty }+4\int _{0}^{\infty }{}dx{\frac {x}{\left({{e}^{x}}+1\right)}}\\&\left[{{x}^{2}}{\frac {1}{\left({{e}^{x}}+1\right)}}\right]_{0}^{\infty }=0\\&\int _{0}^{\infty }{}dx{\frac {x}{\left({{e}^{x}}+1\right)}}={\frac {{\pi }^{2}}{12}}\\&\Rightarrow I={\frac {{\pi }^{2}}{3}}\\\end{aligned}}

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I=dxx2ex(ex+1)2=20dxx2ex(ex+1)2=2[x21(ex+1)]0+40dxx(ex+1)[x21(ex+1)]0=00dxx(ex+1)=π212I=π23
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