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Display information for equation id:math.2090.14 on revision:2090

* Page found: Magnetische Induktion (eq math.2090.14)

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TeX (original user input):

\begin{align}
& d\bar{r}\times \left( d\bar{r}\acute{\ }\times \left( \bar{r}-\bar{r} \right) \right)=\left( d\bar{r}\left( \bar{r}-\bar{r} \right) \right)d\bar{r}\acute{\ }-\left( d\bar{r}d\bar{r}\acute{\ } \right)\left( \bar{r}-\bar{r} \right) \\
& und \\
& \int_{L}^{{}}{{}}d\bar{r}\frac{\bar{r}-\bar{r}\acute{\ }}{{{\left| \bar{r}-\bar{r}\acute{\ } \right|}^{3}}}=-\left. \frac{1}{\left| \bar{r}-\bar{r}\acute{\ } \right|} \right|_{L-ANfang}^{L-Ende}=0 \\
\end{align}

TeX (checked):

{\begin{aligned}&d{\bar {r}}\times \left(d{\bar {r}}{\acute {\ }}\times \left({\bar {r}}-{\bar {r}}\right)\right)=\left(d{\bar {r}}\left({\bar {r}}-{\bar {r}}\right)\right)d{\bar {r}}{\acute {\ }}-\left(d{\bar {r}}d{\bar {r}}{\acute {\ }}\right)\left({\bar {r}}-{\bar {r}}\right)\\&und\\&\int _{L}^{}{}d{\bar {r}}{\frac {{\bar {r}}-{\bar {r}}{\acute {\ }}}{{\left|{\bar {r}}-{\bar {r}}{\acute {\ }}\right|}^{3}}}=-\left.{\frac {1}{\left|{\bar {r}}-{\bar {r}}{\acute {\ }}\right|}}\right|_{L-ANfang}^{L-Ende}=0\\\end{aligned}}

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dr¯×(dr¯´×(r¯r¯))=(dr¯(r¯r¯))dr¯´(dr¯dr¯´)(r¯r¯)undLdr¯r¯r¯´|r¯r¯´|3=1|r¯r¯´||LANfangLEnde=0
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