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Display information for equation id:math.1826.51 on revision:1826

* Page found: Das Wasserstoffatom (relativistsich) (eq math.1826.51)

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TeX (original user input):

\begin{align}

& a\left[ \left( \lambda +q+k+1 \right){{g}_{k+1}}-{{g}_{k}}+\gamma {{f}_{k+1}}-\frac{{{a}_{2}}}{a}{{f}_{k}} \right]-{{a}_{2}}\left[ \left( \lambda -q+k+1 \right){{f}_{k+1}}-{{f}_{k}}+\gamma {{g}_{k+1}}-\frac{{{a}_{1}}}{a}{{g}_{k}} \right]=0 \\

& \Rightarrow \left[ a\left( \lambda +q+k+1 \right)+{{a}_{2}}\gamma  \right]{{g}_{k+1}}=\left[ {{a}_{2}}\left( \lambda -q+k+1 \right)-a\gamma  \right]{{f}_{k+1}} \\

\end{align}

TeX (checked):

{\begin{aligned}&a\left[\left(\lambda +q+k+1\right){{g}_{k+1}}-{{g}_{k}}+\gamma {{f}_{k+1}}-{\frac {{a}_{2}}{a}}{{f}_{k}}\right]-{{a}_{2}}\left[\left(\lambda -q+k+1\right){{f}_{k+1}}-{{f}_{k}}+\gamma {{g}_{k+1}}-{\frac {{a}_{1}}{a}}{{g}_{k}}\right]=0\\&\Rightarrow \left[a\left(\lambda +q+k+1\right)+{{a}_{2}}\gamma \right]{{g}_{k+1}}=\left[{{a}_{2}}\left(\lambda -q+k+1\right)-a\gamma \right]{{f}_{k+1}}\\\end{aligned}}

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a[(λ+q+k+1)gk+1gk+γfk+1a2afk]a2[(λq+k+1)fk+1fk+γgk+1a1agk]=0[a(λ+q+k+1)+a2γ]gk+1=[a2(λq+k+1)aγ]fk+1
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Identifiers

  • a
  • λ
  • q
  • k
  • gk+1
  • gk
  • γ
  • fk+1
  • a2
  • a
  • fk
  • a2
  • λ
  • q
  • k
  • fk+1
  • fk
  • γ
  • gk+1
  • a1
  • a
  • gk
  • a
  • λ
  • q
  • k
  • a2
  • γ
  • gk+1
  • a2
  • λ
  • q
  • k
  • a
  • γ
  • fk+1

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