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Display information for equation id:math.1807.29 on revision:1807

* Page found: Dirac- Gleichung für Elektronen (eq math.1807.29)

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Hash: a004af38c737c4fcb63209261a850688

TeX (original user input):

\begin{align}

& \sum\limits_{\mu ,\nu =1}^{3}{{}}\left( {{\alpha }^{\mu }}{{\alpha }^{\nu }}{{p}^{\mu }}{{p}^{\nu }} \right)={{p}^{2}} \\

& \Rightarrow {{\left( {{\alpha }^{\mu }} \right)}^{2}}=1 \\

& \ {{\alpha }^{\mu }}{{\alpha }^{\nu }}+{{\alpha }^{\nu }}{{\alpha }^{\mu }}=0\ f\ddot{u}r\ \nu \ne \mu  \\

& {{\alpha }^{\mu }}\beta +\beta {{\alpha }^{\mu }}=0 \\

& {{\beta }^{2}}=1 \\

\end{align}

TeX (checked):

{\begin{aligned}&\sum \limits _{\mu ,\nu =1}^{3}{}\left({{\alpha }^{\mu }}{{\alpha }^{\nu }}{{p}^{\mu }}{{p}^{\nu }}\right)={{p}^{2}}\\&\Rightarrow {{\left({{\alpha }^{\mu }}\right)}^{2}}=1\\&\ {{\alpha }^{\mu }}{{\alpha }^{\nu }}+{{\alpha }^{\nu }}{{\alpha }^{\mu }}=0\ f{\ddot {u}}r\ \nu \neq \mu \\&{{\alpha }^{\mu }}\beta +\beta {{\alpha }^{\mu }}=0\\&{{\beta }^{2}}=1\\\end{aligned}}

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μ,ν=13(αμανpμpν)=p2(αμ)2=1αμαν+αναμ=0fu¨rνμαμβ+βαμ=0β2=1
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