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Display information for equation id:math.1632.13 on revision:1632

* Page found: Eigenwerte und Eigenzustände von hermiteschen Operatoren (eq math.1632.13)

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TeX (original user input):

\begin{align}
& \left\langle  {{\Psi }_{1}} \right|\hat{F}\left| {{\Psi }_{2}} \right\rangle ={{F}_{2}}\left\langle  {{\Psi }_{1}}  |  {{\Psi }_{2}} \right\rangle  \\
& \left\langle  {{\Psi }_{2}} \right|\hat{F}\left| {{\Psi }_{1}} \right\rangle ={{F}_{1}}\left\langle  {{\Psi }_{2}} | {{\Psi }_{1}} \right\rangle =\left\langle  {{\Psi }_{1}} \right|\hat{F}\left| {{\Psi }_{2}} \right\rangle *={{F}_{2}}\left\langle  {{\Psi }_{1}}  |  {{\Psi }_{2}} \right\rangle \quad falls\ \hat{F}={{{\hat{F}}}^{+}},{{F}_{2}}={{F}_{2}}* \\
& \left\langle  {{\Psi }_{2}} \right|\hat{F}\left| {{\Psi }_{1}} \right\rangle =\left\langle  {{{\hat{F}}}^{+}}{{\Psi }_{2}}  |  {{\Psi }_{1}} \right\rangle ={{F}_{2}}\left\langle  {{\Psi }_{2}} | {{\Psi }_{1}} \right\rangle  \\
& \left\langle  {{\Psi }_{2}} \right|\hat{F}\left| {{\Psi }_{1}} \right\rangle -\left\langle  {{\Psi }_{2}} \right|\hat{F}\left| {{\Psi }_{1}} \right\rangle =\left( {{F}_{2}}-{{F}_{1}} \right)\left\langle  {{\Psi }_{2}} | {{\Psi }_{1}} \right\rangle  \\ 

\end{align}

TeX (checked):

{\begin{aligned}&\left\langle {{\Psi }_{1}}\right|{\hat {F}}\left|{{\Psi }_{2}}\right\rangle ={{F}_{2}}\left\langle {{\Psi }_{1}}|{{\Psi }_{2}}\right\rangle \\&\left\langle {{\Psi }_{2}}\right|{\hat {F}}\left|{{\Psi }_{1}}\right\rangle ={{F}_{1}}\left\langle {{\Psi }_{2}}|{{\Psi }_{1}}\right\rangle =\left\langle {{\Psi }_{1}}\right|{\hat {F}}\left|{{\Psi }_{2}}\right\rangle *={{F}_{2}}\left\langle {{\Psi }_{1}}|{{\Psi }_{2}}\right\rangle \quad falls\ {\hat {F}}={{\hat {F}}^{+}},{{F}_{2}}={{F}_{2}}*\\&\left\langle {{\Psi }_{2}}\right|{\hat {F}}\left|{{\Psi }_{1}}\right\rangle =\left\langle {{\hat {F}}^{+}}{{\Psi }_{2}}|{{\Psi }_{1}}\right\rangle ={{F}_{2}}\left\langle {{\Psi }_{2}}|{{\Psi }_{1}}\right\rangle \\&\left\langle {{\Psi }_{2}}\right|{\hat {F}}\left|{{\Psi }_{1}}\right\rangle -\left\langle {{\Psi }_{2}}\right|{\hat {F}}\left|{{\Psi }_{1}}\right\rangle =\left({{F}_{2}}-{{F}_{1}}\right)\left\langle {{\Psi }_{2}}|{{\Psi }_{1}}\right\rangle \\\end{aligned}}

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Ψ1|F^|Ψ2=F2Ψ1|Ψ2Ψ2|F^|Ψ1=F1Ψ2|Ψ1=Ψ1|F^|Ψ2*=F2Ψ1|Ψ2fallsF^=F^+,F2=F2*Ψ2|F^|Ψ1=F^+Ψ2|Ψ1=F2Ψ2|Ψ1Ψ2|F^|Ψ1Ψ2|F^|Ψ1=(F2F1)Ψ2|Ψ1
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  • Ψ2
  • F^
  • Ψ1
  • F1
  • Ψ2
  • Ψ1
  • Ψ1
  • F^
  • Ψ2
  • F2
  • Ψ1
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  • f
  • a
  • l
  • l
  • s
  • F^
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  • F2
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  • Ψ2
  • F^
  • Ψ1
  • F^
  • Ψ2
  • Ψ1
  • F2
  • Ψ2
  • Ψ1
  • Ψ2
  • F^
  • Ψ1
  • Ψ2
  • F^
  • Ψ1
  • F2
  • F1
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  • Ψ1

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