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Display information for equation id:math.1632.13 on revision:1632
* Page found: Eigenwerte und Eigenzustände von hermiteschen Operatoren (eq math.1632.13)
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Hash: 503704582177163abf389d3d2825616c
TeX (original user input):
\begin{align}
& \left\langle {{\Psi }_{1}} \right|\hat{F}\left| {{\Psi }_{2}} \right\rangle ={{F}_{2}}\left\langle {{\Psi }_{1}} | {{\Psi }_{2}} \right\rangle \\
& \left\langle {{\Psi }_{2}} \right|\hat{F}\left| {{\Psi }_{1}} \right\rangle ={{F}_{1}}\left\langle {{\Psi }_{2}} | {{\Psi }_{1}} \right\rangle =\left\langle {{\Psi }_{1}} \right|\hat{F}\left| {{\Psi }_{2}} \right\rangle *={{F}_{2}}\left\langle {{\Psi }_{1}} | {{\Psi }_{2}} \right\rangle \quad falls\ \hat{F}={{{\hat{F}}}^{+}},{{F}_{2}}={{F}_{2}}* \\
& \left\langle {{\Psi }_{2}} \right|\hat{F}\left| {{\Psi }_{1}} \right\rangle =\left\langle {{{\hat{F}}}^{+}}{{\Psi }_{2}} | {{\Psi }_{1}} \right\rangle ={{F}_{2}}\left\langle {{\Psi }_{2}} | {{\Psi }_{1}} \right\rangle \\
& \left\langle {{\Psi }_{2}} \right|\hat{F}\left| {{\Psi }_{1}} \right\rangle -\left\langle {{\Psi }_{2}} \right|\hat{F}\left| {{\Psi }_{1}} \right\rangle =\left( {{F}_{2}}-{{F}_{1}} \right)\left\langle {{\Psi }_{2}} | {{\Psi }_{1}} \right\rangle \\
\end{align}
TeX (checked):
{\begin{aligned}&\left\langle {{\Psi }_{1}}\right|{\hat {F}}\left|{{\Psi }_{2}}\right\rangle ={{F}_{2}}\left\langle {{\Psi }_{1}}|{{\Psi }_{2}}\right\rangle \\&\left\langle {{\Psi }_{2}}\right|{\hat {F}}\left|{{\Psi }_{1}}\right\rangle ={{F}_{1}}\left\langle {{\Psi }_{2}}|{{\Psi }_{1}}\right\rangle =\left\langle {{\Psi }_{1}}\right|{\hat {F}}\left|{{\Psi }_{2}}\right\rangle *={{F}_{2}}\left\langle {{\Psi }_{1}}|{{\Psi }_{2}}\right\rangle \quad falls\ {\hat {F}}={{\hat {F}}^{+}},{{F}_{2}}={{F}_{2}}*\\&\left\langle {{\Psi }_{2}}\right|{\hat {F}}\left|{{\Psi }_{1}}\right\rangle =\left\langle {{\hat {F}}^{+}}{{\Psi }_{2}}|{{\Psi }_{1}}\right\rangle ={{F}_{2}}\left\langle {{\Psi }_{2}}|{{\Psi }_{1}}\right\rangle \\&\left\langle {{\Psi }_{2}}\right|{\hat {F}}\left|{{\Psi }_{1}}\right\rangle -\left\langle {{\Psi }_{2}}\right|{\hat {F}}\left|{{\Psi }_{1}}\right\rangle =\left({{F}_{2}}-{{F}_{1}}\right)\left\langle {{\Psi }_{2}}|{{\Psi }_{1}}\right\rangle \\\end{aligned}}
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