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Display information for equation id:math.1619.85 on revision:1619
* Page found: Zustandsvektoren im Hilbertraum (eq math.1619.85)
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Hash: 0e7a70b3d986976d59526daa99b4d7c0
TeX (original user input):
\bar{a}=\sum\limits_{j}{{}}{{a}_{j}}\left| {{{\bar{e}}}_{j}} \right\rangle =\sum\limits_{j}{\left| {{{\bar{e}}}_{j}} \right\rangle \left\langle {{{\bar{e}}}_{j}} | {\bar{a}} \right\rangle =\sum\limits_{j}{{}}{{a}_{j}}\acute{\ }\left| {{{\bar{e}}}_{j}}\acute{\ } \right\rangle }=\sum\limits_{j}{\left| {{{\bar{e}}}_{j}}\acute{\ } \right\rangle \left\langle {{{\bar{e}}}_{j}}\acute{\ } | {\bar{a}} \right\rangle }
TeX (checked):
{\bar {a}}=\sum \limits _{j}{}{{a}_{j}}\left|{{\bar {e}}_{j}}\right\rangle =\sum \limits _{j}{\left|{{\bar {e}}_{j}}\right\rangle \left\langle {{\bar {e}}_{j}}|{\bar {a}}\right\rangle =\sum \limits _{j}{}{{a}_{j}}{\acute {\ }}\left|{{\bar {e}}_{j}}{\acute {\ }}\right\rangle }=\sum \limits _{j}{\left|{{\bar {e}}_{j}}{\acute {\ }}\right\rangle \left\langle {{\bar {e}}_{j}}{\acute {\ }}|{\bar {a}}\right\rangle }
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