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Display information for equation id:math.1346.79 on revision:1346
* Page found: Mechanik des starren Körpers (eq math.1346.79)
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Hash: e5da52a9653f949f8d2218f8e3e97615
TeX (original user input):
\begin{align}
& \rho (\bar{x})=\rho (r) \\
& {{J}_{1}}={{J}_{2}}={{J}_{3}}=:J \\
& 3J={{J}_{1}}+{{J}_{2}}+{{J}_{3}}=\int_{{}}^{{}}{{{d}^{3}}x}\rho (r)\left[ \left( {{x}_{2}}^{2}+{{x}_{3}}^{2} \right)+\left( {{x}_{1}}^{2}+{{x}_{3}}^{2} \right)+\left( {{x}_{1}}^{2}+{{x}_{2}}^{2} \right) \right]=\int_{{}}^{{}}{{{d}^{3}}x}\rho (r)2{{r}^{2}} \\
& 3J=2\cdot 4\pi \int_{0}^{R}{dr{{r}^{4}}\rho (r)} \\
\end{align}
TeX (checked):
{\begin{aligned}&\rho ({\bar {x}})=\rho (r)\\&{{J}_{1}}={{J}_{2}}={{J}_{3}}=:J\\&3J={{J}_{1}}+{{J}_{2}}+{{J}_{3}}=\int _{}^{}{{{d}^{3}}x}\rho (r)\left[\left({{x}_{2}}^{2}+{{x}_{3}}^{2}\right)+\left({{x}_{1}}^{2}+{{x}_{3}}^{2}\right)+\left({{x}_{1}}^{2}+{{x}_{2}}^{2}\right)\right]=\int _{}^{}{{{d}^{3}}x}\rho (r)2{{r}^{2}}\\&3J=2\cdot 4\pi \int _{0}^{R}{dr{{r}^{4}}\rho (r)}\\\end{aligned}}
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