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Display information for equation id:math.1199.663 on revision:1199

* Page found: Elektrodynamik Schöll (eq math.1199.663)

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TeX (original user input):

\begin{align}
& u\left( \bar{r},t \right)=\frac{1}{{{\left( 2\pi  \right)}^{2}}}\int_{{{R}^{3}}}^{{}}{{{d}^{3}}q\int_{-\infty }^{\infty }{d\omega }}\hat{u}\left( \bar{q},\omega  \right){{e}^{i\left( \bar{q}\bar{r}-\omega t \right)}} \\
& \Rightarrow \#u\left( \bar{r},t \right)=\frac{1}{{{\left( 2\pi  \right)}^{2}}}\int_{{{R}^{3}}}^{{}}{{{d}^{3}}q\int_{-\infty }^{\infty }{d\omega }}\hat{u}\left( \bar{q},\omega  \right)\#{{e}^{i\left( \bar{q}\bar{r}-\omega t \right)}} \\
& \#{{e}^{i\left( \bar{q}\bar{r}-\omega t \right)}}=-\left( {{q}^{2}}-\frac{{{\omega }^{2}}}{{{c}^{2}}} \right){{e}^{i\left( \bar{q}\bar{r}-\omega t \right)}} \\
\end{align}

TeX (checked):

{\begin{aligned}&u\left({\bar {r}},t\right)={\frac {1}{{\left(2\pi \right)}^{2}}}\int _{{R}^{3}}^{}{{{d}^{3}}q\int _{-\infty }^{\infty }{d\omega }}{\hat {u}}\left({\bar {q}},\omega \right){{e}^{i\left({\bar {q}}{\bar {r}}-\omega t\right)}}\\&\Rightarrow \#u\left({\bar {r}},t\right)={\frac {1}{{\left(2\pi \right)}^{2}}}\int _{{R}^{3}}^{}{{{d}^{3}}q\int _{-\infty }^{\infty }{d\omega }}{\hat {u}}\left({\bar {q}},\omega \right)\#{{e}^{i\left({\bar {q}}{\bar {r}}-\omega t\right)}}\\&\#{{e}^{i\left({\bar {q}}{\bar {r}}-\omega t\right)}}=-\left({{q}^{2}}-{\frac {{\omega }^{2}}{{c}^{2}}}\right){{e}^{i\left({\bar {q}}{\bar {r}}-\omega t\right)}}\\\end{aligned}}

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u(r¯,t)=1(2π)2R3d3qdωu^(q¯,ω)ei(q¯r¯ωt)#u(r¯,t)=1(2π)2R3d3qdωu^(q¯,ω)#ei(q¯r¯ωt)#ei(q¯r¯ωt)=(q2ω2c2)ei(q¯r¯ωt)
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