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Display information for equation id:math.1199.390 on revision:1199

* Page found: Elektrodynamik Schöll (eq math.1199.390)

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TeX (original user input): 

\begin{align}
& \bar{F}=\int_{{}}^{{}}{{}}{{d}^{3}}r\acute{\ }\bar{j}(\bar{r}\acute{\ })\times {{\nabla }_{r}}\left[ \left( \bar{r}\acute{\ } \right)\cdot \bar{B}(\bar{r}) \right] \\
& \bar{j}(\bar{r}\acute{\ })\times {{\nabla }_{r}}\left[ \left( \bar{r}\acute{\ } \right)\cdot \bar{B}(\bar{r}) \right]=-{{\nabla }_{r}}\times \left[ \left( \left( \bar{r}\acute{\ } \right)\cdot \bar{B}(\bar{r}) \right)\bar{j}(\bar{r}\acute{\ }) \right]+\left[ \left( \bar{r}\acute{\ } \right)\cdot \bar{B}(\bar{r}) \right]{{\nabla }_{r}}\times \bar{j}(\bar{r}\acute{\ }) \\
& {{\nabla }_{r}}\times \bar{j}(\bar{r}\acute{\ })=0 \\
& \Rightarrow \bar{F}=-\int_{{}}^{{}}{{}}{{d}^{3}}r\acute{\ }{{\nabla }_{r}}\times \left[ \left( \left( \bar{r}\acute{\ } \right)\cdot \bar{B}(\bar{r}) \right)\bar{j}(\bar{r}\acute{\ }) \right]=-{{\nabla }_{r}}\times \left( \bar{m}\times \bar{B}(\bar{r}) \right) \\
& \bar{F}=-{{\nabla }_{r}}\times \left( \bar{m}\times \bar{B}(\bar{r}) \right)=\left( \bar{m}\cdot {{\nabla }_{r}} \right)\bar{B}(\bar{r})=-{{\nabla }_{r}}\left( -\bar{m}\cdot \bar{B}(\bar{r}) \right) \\
\end{align}

TeX (checked): 

{\begin{aligned}&{\bar {F}}=\int _{}^{}{}{{d}^{3}}r{\acute {\ }}{\bar {j}}({\bar {r}}{\acute {\ }})\times {{\nabla }_{r}}\left[\left({\bar {r}}{\acute {\ }}\right)\cdot {\bar {B}}({\bar {r}})\right]\\&{\bar {j}}({\bar {r}}{\acute {\ }})\times {{\nabla }_{r}}\left[\left({\bar {r}}{\acute {\ }}\right)\cdot {\bar {B}}({\bar {r}})\right]=-{{\nabla }_{r}}\times \left[\left(\left({\bar {r}}{\acute {\ }}\right)\cdot {\bar {B}}({\bar {r}})\right){\bar {j}}({\bar {r}}{\acute {\ }})\right]+\left[\left({\bar {r}}{\acute {\ }}\right)\cdot {\bar {B}}({\bar {r}})\right]{{\nabla }_{r}}\times {\bar {j}}({\bar {r}}{\acute {\ }})\\&{{\nabla }_{r}}\times {\bar {j}}({\bar {r}}{\acute {\ }})=0\\&\Rightarrow {\bar {F}}=-\int _{}^{}{}{{d}^{3}}r{\acute {\ }}{{\nabla }_{r}}\times \left[\left(\left({\bar {r}}{\acute {\ }}\right)\cdot {\bar {B}}({\bar {r}})\right){\bar {j}}({\bar {r}}{\acute {\ }})\right]=-{{\nabla }_{r}}\times \left({\bar {m}}\times {\bar {B}}({\bar {r}})\right)\\&{\bar {F}}=-{{\nabla }_{r}}\times \left({\bar {m}}\times {\bar {B}}({\bar {r}})\right)=\left({\bar {m}}\cdot {{\nabla }_{r}}\right){\bar {B}}({\bar {r}})=-{{\nabla }_{r}}\left(-{\bar {m}}\cdot {\bar {B}}({\bar {r}})\right)\\\end{aligned}}

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F¯=∫d3r´j¯(r¯´)×∇r[(r¯´)⋅B¯(r¯)]j¯(r¯´)×∇r[(r¯´)⋅B¯(r¯)]=−∇r×[((r¯´)⋅B¯(r¯))j¯(r¯´)]+[(r¯´)⋅B¯(r¯)]∇r×j¯(r¯´)∇r×j¯(r¯´)=0⇒F¯=−∫d3r´∇r×[((r¯´)⋅B¯(r¯))j¯(r¯´)]=−∇r×(m¯×B¯(r¯))F¯=−∇r×(m¯×B¯(r¯))=(m¯⋅∇r)B¯(r¯)=−∇r(−m¯⋅B¯(r¯))
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